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7x^2+63x+98=0
a = 7; b = 63; c = +98;
Δ = b2-4ac
Δ = 632-4·7·98
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-35}{2*7}=\frac{-98}{14} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+35}{2*7}=\frac{-28}{14} =-2 $
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